What is the derivative of (x^2-x+1^3) ?

The derivative of (x^2-x+1^3) is 3(x^2-x+1)^2(2x-1)

What is the first derivative of (x^2-x+1^3) ?

The first derivative of (x^2-x+1^3) is 3(x^2-x+1)^2(2x-1)

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\frac{d}{d x} ((x^{2} - x + 1)^{3})

3 (x^{2} - x + 1)^{2} (2 x - 1)

Solution steps

\frac{d}{d x} ((x^{2} - x + 1)^{3})

Apply the chain rule:

3 (x^{2} - x + 1)^{2} \frac{d}{d x} (x^{2} - x + 1)

= 3 (x^{2} - x + 1)^{2} \frac{d}{d x} (x^{2} - x + 1)

\frac{d}{d x} (x^{2} - x + 1) = 2 x - 1

= 3 (x^{2} - x + 1)^{2} (2 x - 1)

(cos (5 x)) y^{^{'}} + 5 (tan (5 x)) y = - 9 sec (5 x)

y = (1 + x^{2}) (3 - 2 x)

\frac{d}{d x} (5 x^{3} - 6 x)

n = 1 \sum \infty \frac{9}{n ^{2}}

\frac{2 x ^{2} + 8 x + 8}{x}

What is the derivative of (x^2-x+1^3) ?
The derivative of (x^2-x+1^3) is 3(x^2-x+1)^2(2x-1)
What is the first derivative of (x^2-x+1^3) ?
The first derivative of (x^2-x+1^3) is 3(x^2-x+1)^2(2x-1)