What is the limit as x approaches 1 of 1/(x^2+1) ?

The limit as x approaches 1 of 1/(x^2+1) is 1/2

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limit as x approaches 1 of 1/(x^2+1)

x \to 1 lim (\frac{1}{x ^{2} + 1})

\frac{1}{2}

Decimal Notation

0.5

Solution steps

x \to 1 lim (\frac{1}{x ^{2} + 1})

Plug in the value

x = 1

= \frac{1}{1 ^{2} + 1}

Simplify

= \frac{1}{2}

\int_{6}^{7} t^{3} d t

\frac{\partial}{\partial x} (\frac{4 x - 5 y}{4 x + 5 y})

\frac{4}{( s ) ( s ^{2} + 2 s + 4 )}

y^{^{''}} - 2 y^{^{'}} + y = \frac{( - 2 e ^{- t} )}{( t ^{2} + 1 )}

(x^{2} + y^{2} + x) d x + y d y = 0

What is the limit as x approaches 1 of 1/(x^2+1) ?
The limit as x approaches 1 of 1/(x^2+1) is 1/2