What is (\partial)/(\partial y)(e^{x+y}-1) ?

The answer to (\partial)/(\partial y)(e^{x+y}-1) is e^{x+y}

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(\partial)/(\partial y)(e^{x+y}-1)

\frac{\partial}{\partial y} (e^{x + y} - 1)

e^{x + y}

Solution steps

\frac{\partial}{\partial y} (e^{x + y} - 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x + y}) - \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (e^{x + y}) = e^{x + y}

\frac{\partial}{\partial y} (1) = 0

= e^{x + y} - 0

Simplify

= e^{x + y}

f (x) = 9 x + 8

x \to - \infty lim (- 2 (x))

\int sin (9 π t) d t

x \to 3 lim (\frac{x - 5}{x - 3})

\frac{d}{d x} (\frac{ln ( x )}{x ^{5}})

What is (\partial)/(\partial y)(e^{x+y}-1) ?
The answer to (\partial)/(\partial y)(e^{x+y}-1) is e^{x+y}