What is the derivative of (2x)/((x^3-6)^2) ?

The derivative of (2x)/((x^3-6)^2) is (2(-5x^3-6))/((x^3-6)^3)

What is the first derivative of (2x)/((x^3-6)^2) ?

The first derivative of (2x)/((x^3-6)^2) is (2(-5x^3-6))/((x^3-6)^3)

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derivative of

\frac{2 x}{( x ^{3} - 6 ) ^{2}}

\frac{2 ( - 5 x ^{3} - 6 )}{( x ^{3} - 6 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{2 x}{( x ^{3} - 6 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{( x ^{3} - 6 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d x}{d x} ( x ^{3} - 6 ) ^{2} - \frac{d}{d x} ( ( x ^{3} - 6 ) ^{2} ) x}{( ( x ^{3} - 6 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{3} - 6)^{2}) = 6 x^{2} (x^{3} - 6)

= 2 \cdot \frac{1 \cdot ( x ^{3} - 6 ) ^{2} - 6 x ^{2} ( x ^{3} - 6 ) x}{( ( x ^{3} - 6 ) ^{2} ) ^{2}}

Simplify

2 \cdot \frac{1 \cdot ( x ^{3} - 6 ) ^{2} - 6 x ^{2} ( x ^{3} - 6 ) x}{( ( x ^{3} - 6 ) ^{2} ) ^{2}} : \frac{2 ( - 5 x ^{3} - 6 )}{( x ^{3} - 6 ) ^{3}}

= \frac{2 ( - 5 x ^{3} - 6 )}{( x ^{3} - 6 ) ^{3}}

\frac{d}{d x} (\frac{sin ^{2} ( x )}{x})

\frac{1}{3} x^{3} + 8 x^{2} + 63 x + 7

\int_{- 4 π}^{4 π} sin^{2} (x) + 1 d x

x \to 2 - lim (4)

y^{^{''}} x + (\frac{2}{x} - \frac{2 x}{1 + x ^{2}}) \cdot y^{^{'}} = 0

What is the derivative of (2x)/((x^3-6)^2) ?
The derivative of (2x)/((x^3-6)^2) is (2(-5x^3-6))/((x^3-6)^3)
What is the first derivative of (2x)/((x^3-6)^2) ?
The first derivative of (2x)/((x^3-6)^2) is (2(-5x^3-6))/((x^3-6)^3)