What is the derivative of 2cos(x-4sin(x)) ?

The derivative of 2cos(x-4sin(x)) is -2sin(x)-4cos(x)

What is the first derivative of 2cos(x-4sin(x)) ?

The first derivative of 2cos(x-4sin(x)) is -2sin(x)-4cos(x)

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\frac{d}{d x} (2 cos (x) - 4 sin (x))

- 2 sin (x) - 4 cos (x)

Solution steps

\frac{d}{d x} (2 cos (x) - 4 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (x)) - \frac{d}{d x} (4 sin (x))

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

\frac{d}{d x} (4 sin (x)) = 4 cos (x)

= - 2 sin (x) - 4 cos (x)

\int 2 arcsin (2 x) d x

\int \frac{x}{7 - x - x ^{2}} d x

\int \frac{1}{169 - 16 x ^{2}} d x

\frac{d}{d x} (e^{x a})

t y^{^{''}} + 4 y^{^{'}} = t^{2}

What is the derivative of 2cos(x-4sin(x)) ?
The derivative of 2cos(x-4sin(x)) is -2sin(x)-4cos(x)
What is the first derivative of 2cos(x-4sin(x)) ?
The first derivative of 2cos(x-4sin(x)) is -2sin(x)-4cos(x)