What is the integral from 0 to 7 of-30x^2+420x ?

The integral from 0 to 7 of-30x^2+420x is 6860

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integral from 0 to 7 of-30x^2+420x

\int_{0}^{7} - 30 x^{2} + 420 x d x

6860

Solution steps

\int_{0}^{7} - 30 x^{2} + 420 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{7} 30 x^{2} d x + \int_{0}^{7} 420 x d x

\int_{0}^{7} 30 x^{2} d x = 3430

\int_{0}^{7} 420 x d x = 10290

= - 3430 + 10290

Simplify

= 6860

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What is the integral from 0 to 7 of-30x^2+420x ?
The integral from 0 to 7 of-30x^2+420x is 6860