What is the solution for y^'=(7x)/y ?

The solution for y^'=(7x)/y is y=sqrt(7x^2+c_{1)},y=-sqrt(7x^2+c_{1)}

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y^'=(7x)/y

y^{^{'}} = \frac{7 x}{y}

y = 7 x^{2} + c_{1}, y = - 7 x^{2} + c_{1}

Solution steps

y^{'} (x) = \frac{7 x}{y}

Solve separable ODE:

y = 7 x^{2} + c_{1}, y = - 7 x^{2} + c_{1}

y = 7 x^{2} + c_{1}, y = - 7 x^{2} + c_{1}

\int \frac{x ^{2}}{8 x ^{3} - 1} d x

(2.4) (1.6)

f (x) = \frac{2}{x - 1}, at x = 3

\int 2 sin^{2} (t) d t

\frac{d}{d x} (x^{3} + 4 x)

What is the solution for y^'=(7x)/y ?
The solution for y^'=(7x)/y is y=sqrt(7x^2+c_{1)},y=-sqrt(7x^2+c_{1)}