What is the integral from 1 to 4 of 5/(x^2) ?

The integral from 1 to 4 of 5/(x^2) is 15/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of 5/(x^2)

\int_{1}^{4} \frac{5}{x ^{2}} d x

\frac{15}{4}

Solution steps

\int_{1}^{4} \frac{5}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{1}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{4}

= 5 [- \frac{1}{x}]_{1}^{4}

Compute the boundaries:

\frac{3}{4}

= 5 \cdot \frac{3}{4}

Simplify

= \frac{15}{4}

\int e^{- x} (1 + e^{2 x}) d x

\frac{d}{d x} (\frac{1}{4 x + 4})

f (y) = e^{y}

\int \frac{x - 1}{x ^{2} + x + 1} d x

f (x) = (x (x^{5} + 9)^{3})

What is the integral from 1 to 4 of 5/(x^2) ?
The integral from 1 to 4 of 5/(x^2) is 15/4