What is area f(x)=e^{6x}sin(x),0,pi ?

The answer to area f(x)=e^{6x}sin(x),0,pi is (e^{6pi}+1)/(37)

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area f(x)=e^{6x}sin(x),0,pi

area

f (x) = e^{6 x} sin (x), 0, π

\frac{e ^{6 π} + 1}{37}

Solution steps

Apply the area formula:

\int_{0}^{π} e^{6 x} ∣ sin (x) ∣ d x

Solve

\int_{0}^{π} e^{6 x} ∣ sin (x) ∣ d x : \frac{e ^{6 π} + 1}{37}

The area is:

= \frac{e ^{6 π} + 1}{37}

\int_{0}^{\infty} e^{- t^{2}} d t

f (x) = - 352

3 e^{x} + 4

x \to 1 - lim (\frac{x - 9}{∣ x - 9 ∣})

\int 2^{3 - 2 x} d x

What is area f(x)=e^{6x}sin(x),0,pi ?
The answer to area f(x)=e^{6x}sin(x),0,pi is (e^{6pi}+1)/(37)