What is the derivative of 8cos(t) ?

The derivative of 8cos(t) is -8sin(t)

What is the first derivative of 8cos(t) ?

The first derivative of 8cos(t) is -8sin(t)

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derivative of

8 cos (t)

- 8 sin (t)

Solution steps

\frac{d}{d t} (8 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= 8 (- sin (t))

Simplify

= - 8 sin (t)

y = 2 x

\int e^{x} e^{3 x} d x

5 x 4 - 5 x, at x = - 2

5 x^{2} \frac{d y}{d x} = \frac{d y}{d x} + 9 x e^{- y}

\frac{d}{d x} (4 sec^{2} (4 x))

What is the derivative of 8cos(t) ?
The derivative of 8cos(t) is -8sin(t)
What is the first derivative of 8cos(t) ?
The first derivative of 8cos(t) is -8sin(t)