What is the tangent of f(x)= 7/x ,\at x=3 ?

The tangent of f(x)= 7/x ,\at x=3 is y=-7/9 x+14/3

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tangent of f(x)= 7/x ,\at x=3

tangent of

f (x) = \frac{7}{x}, at x = 3

y = - \frac{7}{9} x + \frac{14}{3}

Solution steps

Find the tangent point:

(3, \frac{7}{3})

Find the slope of

f (x) = \frac{7}{x} : \frac{df ( x )}{d x} = - \frac{7}{x ^{2}}

Compute the slope of

f (x) = \frac{7}{x}

x = 3 : m = - \frac{7}{9}

Find the line with slope m=

- \frac{7}{9}

and passing through

(3, \frac{7}{3}) : y = - \frac{7}{9} x + \frac{14}{3}

y = - \frac{7}{9} x + \frac{14}{3}

f (x) = (x - 2)^{3} (x + 1)^{2}

\frac{d}{d x} (e^{x} cos (5 x))

\frac{d}{d x} (A x e^{2 x})

f (x) = x + 1, (8, 3)

What is the tangent of f(x)= 7/x ,\at x=3 ?
The tangent of f(x)= 7/x ,\at x=3 is y=-7/9 x+14/3