What is the derivative of e^x+1/(e^x) ?

The derivative of e^x+1/(e^x) is e^x-e^{-x}

What is the first derivative of e^x+1/(e^x) ?

The first derivative of e^x+1/(e^x) is e^x-e^{-x}

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\frac{d}{d x} (e^{x} + \frac{1}{e ^{x}})

e^{x} - e^{- x}

Solution steps

\frac{d}{d x} (e^{x} + \frac{1}{e ^{x}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (\frac{1}{e ^{x}})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (\frac{1}{e ^{x}}) = - e^{- x}

= e^{x} - e^{- x}

\frac{d}{d x} (∣ x - 1 ∣)

(4 y + y x^{2}) d y - (2 x + x y^{2}) d x = 0

x^{2} - x y + y^{2} = 3, (1, 2)

lo g_{2} (x lo g_{5} (x))

y = \frac{2}{sin ( x ) + cos ( x )}, (0, 2)

What is the derivative of e^x+1/(e^x) ?
The derivative of e^x+1/(e^x) is e^x-e^{-x}
What is the first derivative of e^x+1/(e^x) ?
The first derivative of e^x+1/(e^x) is e^x-e^{-x}