What is the d/(dy)(sqrt(29-x^2-4y^2)) ?

The d/(dy)(sqrt(29-x^2-4y^2)) is -(4y)/(sqrt(29-x^2-4y^2))

What is the first d/(dy)(sqrt(29-x^2-4y^2)) ?

The first d/(dy)(sqrt(29-x^2-4y^2)) is -(4y)/(sqrt(29-x^2-4y^2))

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Popular >

\frac{d}{d y} (29 - x^{2} - 4 y^{2})

- \frac{4 y}{29 - x ^{2} - 4 y ^{2}}

Solution steps

\frac{d}{d y} (29 - x^{2} - 4 y^{2})

Treat

x

as a constant

Apply the chain rule:

\frac{1}{2 29 - x ^{2} - 4 y ^{2}} \frac{d}{d y} (29 - x^{2} - 4 y^{2})

= \frac{1}{2 29 - x ^{2} - 4 y ^{2}} \frac{d}{d y} (29 - x^{2} - 4 y^{2})

\frac{d}{d y} (29 - x^{2} - 4 y^{2}) = - 8 y

= \frac{1}{2 29 - x ^{2} - 4 y ^{2}} (- 8 y)

Simplify

\frac{1}{2 29 - x ^{2} - 4 y ^{2}} (- 8 y) : - \frac{4 y}{29 - x ^{2} - 4 y ^{2}}

= - \frac{4 y}{29 - x ^{2} - 4 y ^{2}}

\int (\frac{x}{x - 1}) d x

x^{3} - 25 x + 5, at 5

x \to 0 lim (cos (x) - 1 + x)

cos^{2} (2 t)

\int_{- 2}^{2} (12 - 3 x^{2}) d x

What is the d/(dy)(sqrt(29-x^2-4y^2)) ?
The d/(dy)(sqrt(29-x^2-4y^2)) is -(4y)/(sqrt(29-x^2-4y^2))
What is the first d/(dy)(sqrt(29-x^2-4y^2)) ?
The first d/(dy)(sqrt(29-x^2-4y^2)) is -(4y)/(sqrt(29-x^2-4y^2))