What is the derivative of (-8x/((x^2-4)^2)) ?

The derivative of (-8x/((x^2-4)^2)) is -(8(-3x^2-4))/((x^2-4)^3)

What is the first derivative of (-8x/((x^2-4)^2)) ?

The first derivative of (-8x/((x^2-4)^2)) is -(8(-3x^2-4))/((x^2-4)^3)

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\frac{d}{d x} (\frac{- 8 x}{( x ^{2} - 4 ) ^{2}})

- \frac{8 ( - 3 x ^{2} - 4 )}{( x ^{2} - 4 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{- 8 x}{( x ^{2} - 4 ) ^{2}})

Simplify

\frac{- 8 x}{( x ^{2} - 4 ) ^{2}} : - \frac{8 x}{( x ^{2} - 4 ) ^{2}}

= \frac{d}{d x} (- \frac{8 x}{( x ^{2} - 4 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (\frac{x}{( x ^{2} - 4 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 8 \cdot \frac{\frac{d x}{d x} ( x ^{2} - 4 ) ^{2} - \frac{d}{d x} ( ( x ^{2} - 4 ) ^{2} ) x}{( ( x ^{2} - 4 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} - 4)^{2}) = 4 x (x^{2} - 4)

= - 8 \cdot \frac{1 \cdot ( x ^{2} - 4 ) ^{2} - 4 x ( x ^{2} - 4 ) x}{( ( x ^{2} - 4 ) ^{2} ) ^{2}}

Simplify

- 8 \cdot \frac{1 \cdot ( x ^{2} - 4 ) ^{2} - 4 x ( x ^{2} - 4 ) x}{( ( x ^{2} - 4 ) ^{2} ) ^{2}} : - \frac{8 ( - 3 x ^{2} - 4 )}{( x ^{2} - 4 ) ^{3}}

= - \frac{8 ( - 3 x ^{2} - 4 )}{( x ^{2} - 4 ) ^{3}}

\int_{0}^{1} \frac{1}{e ^{x}} d x

e^{x^{2} y}

\frac{\partial}{\partial x} (2 ln (x) + y)

x \to 1 lim (e^{9 x^{3} - 9 x})

\frac{d ^{2} y}{d t ^{2}} = 150 y

What is the derivative of (-8x/((x^2-4)^2)) ?
The derivative of (-8x/((x^2-4)^2)) is -(8(-3x^2-4))/((x^2-4)^3)
What is the first derivative of (-8x/((x^2-4)^2)) ?
The first derivative of (-8x/((x^2-4)^2)) is -(8(-3x^2-4))/((x^2-4)^3)