What is area f(x)=x-2,g(x)=-x^2+x+2 ?

The answer to area f(x)=x-2,g(x)=-x^2+x+2 is 32/3

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area f(x)=x-2,g(x)=-x^2+x+2

area

f (x) = x - 2, g (x) = - x^{2} + x + 2

\frac{32}{3}

Decimal Notation

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x - 2 - (- x^{2} + x + 2) d x

Solve

\int_{- 2}^{2} x - 2 - (- x^{2} + x + 2) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

\int x^{2} x - 4 d x

\int \frac{sin ^{3} ( x )}{cos ^{5} ( x )} d x

\frac{\partial}{\partial y} (e^{3 x - y^{2}})

\frac{d ^{2}}{d x ^{2}} (\frac{x}{e ^{x}})

What is area f(x)=x-2,g(x)=-x^2+x+2 ?
The answer to area f(x)=x-2,g(x)=-x^2+x+2 is 32/3