What is the derivative of-x^5+3x^4-2x^3-2x^2+3x-1 ?

The derivative of-x^5+3x^4-2x^3-2x^2+3x-1 is -5x^4+12x^3-6x^2-4x+3

What is the first derivative of-x^5+3x^4-2x^3-2x^2+3x-1 ?

The first derivative of-x^5+3x^4-2x^3-2x^2+3x-1 is -5x^4+12x^3-6x^2-4x+3

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\frac{d}{d x} (- x^{5} + 3 x^{4} - 2 x^{3} - 2 x^{2} + 3 x - 1)

- 5 x^{4} + 12 x^{3} - 6 x^{2} - 4 x + 3

Solution steps

\frac{d}{d x} (- x^{5} + 3 x^{4} - 2 x^{3} - 2 x^{2} + 3 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{5}) + \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= - 5 x^{4} + 12 x^{3} - 6 x^{2} - 4 x + 3 - 0

Simplify

= - 5 x^{4} + 12 x^{3} - 6 x^{2} - 4 x + 3

t^{5} e^{- t}

x \to 0 - lim (x)

f (x) = x^{2} + 2 x, g (x) = x + 2

\int \frac{2}{x ^{2} - 4} d x

\frac{d}{d t} N = 400 - \frac{900}{( t ^{2} + 2 ) ^{2}}

What is the derivative of-x^5+3x^4-2x^3-2x^2+3x-1 ?
The derivative of-x^5+3x^4-2x^3-2x^2+3x-1 is -5x^4+12x^3-6x^2-4x+3
What is the first derivative of-x^5+3x^4-2x^3-2x^2+3x-1 ?
The first derivative of-x^5+3x^4-2x^3-2x^2+3x-1 is -5x^4+12x^3-6x^2-4x+3