What is the derivative of 2^x ?

The derivative of 2^x is 2^xln(2)

What is the first derivative of 2^x ?

The first derivative of 2^x is 2^xln(2)

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derivative of

2^{x}

2^{x} ln (2)

Solution steps

\frac{d}{d x} (2^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 2^{x} ln (2)

x \to 4 lim (7 \cdot a + x)

\int x e^{1 - x^{2}} d x

\frac{d}{d x} (ln (3 x^{2} - 5))

\frac{d}{d x} (\frac{1}{x})

\int x (x + 2) d x