What is the derivative of x^4-17x^2+16 ?

The derivative of x^4-17x^2+16 is 4x^3-34x

What is the first derivative of x^4-17x^2+16 ?

The first derivative of x^4-17x^2+16 is 4x^3-34x

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\frac{d}{d x} (x^{4} - 17 x^{2} + 16)

4 x^{3} - 34 x

Solution steps

\frac{d}{d x} (x^{4} - 17 x^{2} + 16)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (17 x^{2}) + \frac{d}{d x} (16)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (17 x^{2}) = 34 x

\frac{d}{d x} (16) = 0

= 4 x^{3} - 34 x + 0

Simplify

= 4 x^{3} - 34 x

\int \frac{a ^{x}}{ln ( a )} d x

f (x) = \frac{x}{x + 6}

\int (ln (x) + 1) e^{x l n (x)} d x

\int x^{- 2} e^{- \frac{1}{x}} d x

\frac{d}{d x} (ln (x x^{2} - 12))

What is the derivative of x^4-17x^2+16 ?
The derivative of x^4-17x^2+16 is 4x^3-34x
What is the first derivative of x^4-17x^2+16 ?
The first derivative of x^4-17x^2+16 is 4x^3-34x