What is the solution for x^2y^{''}-2xy^'-10y=0 ?

The solution for x^2y^{''}-2xy^'-10y=0 is y=c_{1}x^5+(c_{2})/(x^2)

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x^2y^{''}-2xy^'-10y=0

x^{2} y^{^{''}} - 2 x y^{^{'}} - 10 y = 0

y = c_{1} x^{5} + \frac{c _{2}}{x ^{2}}

Solution steps

x^{2} y^{''} (x) - 2 x y^{'} (x) - 10 y = 0

Solve linear ODE:

y = c_{1} x^{5} + \frac{c _{2}}{x ^{2}}

y = c_{1} x^{5} + \frac{c _{2}}{x ^{2}}

\int e^{2 x} + x^{2} d x

n = 1 \sum \infty 9 (\frac{1 - 3}{4})^{n}

\int \frac{cos ( x )}{5 - sin ( x )} d x

\frac{3}{( 3 + ( x + 2 ) ^{2} ) ^{\frac{3}{2}}}, 0

f (x) = 2 x + 5

What is the solution for x^2y^{''}-2xy^'-10y=0 ?
The solution for x^2y^{''}-2xy^'-10y=0 is y=c_{1}x^5+(c_{2})/(x^2)