What is the tangent of y=x^3-13x,(1,-12) ?

The tangent of y=x^3-13x,(1,-12) is y=-10x-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=x^3-13x,(1,-12)

tangent of

y = x^{3} - 13 x, (1, - 12)

y = - 10 x - 2

Solution steps

Find the slope of

y = x^{3} - 13 x : \frac{d y}{d x} = 3 x^{2} - 13

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 10

Find the line with slope m=

- 10

and passing through

(1, - 12) : y = - 10 x - 2

y = - 10 x - 2

y^{^{''}} + 8 y^{^{'}} + 25 y = 0, y (0) = 3, y^{^{'}} (0) = - 11

x^{6} + y^{5} x^{7} + 5 y^{^{'}} = 0

4 e^{- x} + e^{3 x}

\int e^{- t x} sin (x) d x

x \to - 1 lim (3 x^{2} - 1)

What is the tangent of y=x^3-13x,(1,-12) ?
The tangent of y=x^3-13x,(1,-12) is y=-10x-2