What is the solution for y^'-1/(tan(x))y= 1/(tan(x)) ?

The solution for y^'-1/(tan(x))y= 1/(tan(x)) is y=c_{1}sin(x)-1

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y^'-1/(tan(x))y= 1/(tan(x))

y^{^{'}} - \frac{1}{tan ( x )} y = \frac{1}{tan ( x )}

y = c_{1} sin (x) - 1

Solution steps

y^{'} (x) - \frac{1}{tan ( x )} y = \frac{1}{tan ( x )}

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What is the solution for y^'-1/(tan(x))y= 1/(tan(x)) ?
The solution for y^'-1/(tan(x))y= 1/(tan(x)) is y=c_{1}sin(x)-1