What is the derivative of x^2+4x-5 ?

The derivative of x^2+4x-5 is 2x+4

What is the first derivative of x^2+4x-5 ?

The first derivative of x^2+4x-5 is 2x+4

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\frac{d}{d x} (x^{2} + 4 x - 5)

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 2 x + 4 - 0

Simplify

= 2 x + 4

\int sec^{3} (4 x) tan (4 x) d x

\int \frac{1}{5 x} d x

\int_{0}^{2} 2 x^{2} e^{- 2 x} d x

\frac{d}{d x} (\frac{( 2 x ^{2} + 1 ) ^{3}}{x ^{2} - 1})

\int \frac{1}{( 1 + 9 x ^{2} ) ^{\frac{3}{2}}} d x

What is the derivative of x^2+4x-5 ?
The derivative of x^2+4x-5 is 2x+4
What is the first derivative of x^2+4x-5 ?
The first derivative of x^2+4x-5 is 2x+4