What is (\partial)/(\partial x)(xy-2y) ?

The answer to (\partial)/(\partial x)(xy-2y) is y

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(\partial)/(\partial x)(xy-2y)

\frac{\partial}{\partial x} (x y - 2 y)

y

Solution steps

\frac{\partial}{\partial x} (x y - 2 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (2 y)

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (2 y) = 0

= y - 0

Simplify

= y

\frac{d}{d x} (\frac{x ^{4}}{4} - \frac{3 x ^{2}}{2} + 1)

\int 2 cos (π x) d x

3 x^{4} (2 x^{2} - 1)

\int sin (x) \cdot cos (n x) d x

x \to - 3 lim (x^{3} + 27)

What is (\partial)/(\partial x)(xy-2y) ?
The answer to (\partial)/(\partial x)(xy-2y) is y