What is the tangent of f(x)=-2x^2+3 ?

The tangent of f(x)=-2x^2+3 is y=-4a_{0}x+2a_{0}^2+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=-2x^2+3

tangent of

f (x) = - 2 x^{2} + 3

y = - 4 a_{0} x + 2 a_{0}^{2} + 3

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 2 a_{0}^{2} + 3)

Find the slope of

f (x) = - 2 x^{2} + 3 : \frac{df ( x )}{d x} = - 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4 a_{0}

Find the line with slope m=

- 4 a_{0}

and passing through

(a_{0}, - 2 a_{0}^{2} + 3) : y = - 4 a_{0} x + 2 a_{0}^{2} + 3

y = - 4 a_{0} x + 2 a_{0}^{2} + 3

x^{^{''}} - 5 x = 0

2 5^{^{'}}

\frac{\partial}{\partial x} (3 (x - y) e^{3 y + 3 x^{2}})

\frac{d}{d x} (\frac{5 x + 4}{5 x - 4})

\frac{d}{d t} (cosh (t))

What is the tangent of f(x)=-2x^2+3 ?
The tangent of f(x)=-2x^2+3 is y=-4a_{0}x+2a_{0}^2+3