What is the solution for (dy)/(dt)=6y+cos(3t),y(0)= 28/15 ?

The solution for (dy)/(dt)=6y+cos(3t),y(0)= 28/15 is y=(sin(3t))/(15)-(2cos(3t))/(15)+2e^{6t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)=6y+cos(3t),y(0)= 28/15

\frac{d y}{d t} = 6 y + cos (3 t), y (0) = \frac{28}{15}

y = \frac{sin ( 3 t )}{15} - \frac{2 cos ( 3 t )}{15} + 2 e^{6 t}

Solution steps

\frac{d y}{d t} = 6 y + cos (3 t)

Solve linear ODE:

y = \frac{sin ( 3 t )}{15} - \frac{2 cos ( 3 t )}{15} + 2 e^{6 t}

y = \frac{sin ( 3 t )}{15} - \frac{2 cos ( 3 t )}{15} + 2 e^{6 t}

\int 7 5 (8 - 2 x)^{8} d x

f (x) = x^{4} + 6 x^{2} - x, at x = 1

\frac{d}{d x} (ln (\frac{a}{x}))

\frac{d}{d x} (ln (x^{2} \cdot e^{x^{2} + 1}))

\int \frac{5 x ^{2}}{x ^{3} + 3} d x

What is the solution for (dy)/(dt)=6y+cos(3t),y(0)= 28/15 ?
The solution for (dy)/(dt)=6y+cos(3t),y(0)= 28/15 is y=(sin(3t))/(15)-(2cos(3t))/(15)+2e^{6t}