What is the derivative of-x^2+3x-1 ?

The derivative of-x^2+3x-1 is -2x+3

What is the first derivative of-x^2+3x-1 ?

The first derivative of-x^2+3x-1 is -2x+3

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\frac{d}{d x} (- x^{2} + 3 x - 1)

- 2 x + 3

Solution steps

\frac{d}{d x} (- x^{2} + 3 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= - 2 x + 3 - 0

Simplify

= - 2 x + 3

\frac{\partial}{\partial x} (40 x^{\frac{4}{5}} y^{\frac{1}{5}})

3 1 + sin (x)

(1 + \frac{1}{x})^{- 2}

f (x) = 3 x + 1, [0, 3]

f (x) = sin (x), at x = 0

What is the derivative of-x^2+3x-1 ?
The derivative of-x^2+3x-1 is -2x+3
What is the first derivative of-x^2+3x-1 ?
The first derivative of-x^2+3x-1 is -2x+3