What is the integral of (sin(x))/1 ?

The integral of (sin(x))/1 is -cos(x)+C

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integral of (sin(x))/1

\int \frac{sin ( x )}{1} d x

- cos (x) + C

Solution steps

\int \frac{sin ( x )}{1} d x

Simplify

= \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - cos (x)

Add a constant to the solution

= - cos (x) + C

x \to - 2 lim (\frac{x ^{3} + 8}{x + 2})

x \to 2 - lim (f (x) x)

a^{0.5}

\int_{0}^{1} (\frac{6}{1 + x ^{2}}) d x

\frac{d}{d x} (\frac{π ( 4 x ^{2} + 4 x + 1 )}{16 x})