What is the derivative of 10sec(2xtan(2x)) ?

The derivative of 10sec(2xtan(2x)) is 10(2tan^2(2x)sec(2x)+2sec^3(2x))

What is the first derivative of 10sec(2xtan(2x)) ?

The first derivative of 10sec(2xtan(2x)) is 10(2tan^2(2x)sec(2x)+2sec^3(2x))

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\frac{d}{d x} (10 sec (2 x) tan (2 x))

10 (2 tan^{2} (2 x) sec (2 x) + 2 sec^{3} (2 x))

Solution steps

\frac{d}{d x} (10 sec (2 x) tan (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d x} (sec (2 x) tan (2 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sec (2 x), g = tan (2 x)

= 10 (\frac{d}{d x} (sec (2 x)) tan (2 x) + \frac{d}{d x} (tan (2 x)) sec (2 x))

\frac{d}{d x} (sec (2 x)) = sec (2 x) tan (2 x) \cdot 2

\frac{d}{d x} (tan (2 x)) = sec^{2} (2 x) \cdot 2

= 10 (sec (2 x) tan (2 x) \cdot 2 tan (2 x) + sec^{2} (2 x) \cdot 2 sec (2 x))

Simplify

10 (sec (2 x) tan (2 x) \cdot 2 tan (2 x) + sec^{2} (2 x) \cdot 2 sec (2 x)) : 10 (2 tan^{2} (2 x) sec (2 x) + 2 sec^{3} (2 x))

= 10 (2 tan^{2} (2 x) sec (2 x) + 2 sec^{3} (2 x))

\int \frac{a ^{2} x ^{2} - a ^{2}}{x} d x

y^{^{'}} = - \frac{2 t ( 1 + y ^{2} )}{y}

\int 6 x^{2} - 2 x + 8 d x

\frac{2}{x}

x \to 2 lim (x - 3)

What is the derivative of 10sec(2xtan(2x)) ?
The derivative of 10sec(2xtan(2x)) is 10(2tan^2(2x)sec(2x)+2sec^3(2x))
What is the first derivative of 10sec(2xtan(2x)) ?
The first derivative of 10sec(2xtan(2x)) is 10(2tan^2(2x)sec(2x)+2sec^3(2x))