What is (\partial)/(\partial x)(7xy^6+x^4y^4) ?

The answer to (\partial)/(\partial x)(7xy^6+x^4y^4) is 7y^6+4y^4x^3

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(\partial)/(\partial x)(7xy^6+x^4y^4)

\frac{\partial}{\partial x} (7 x y^{6} + x^{4} y^{4})

7 y^{6} + 4 y^{4} x^{3}

Solution steps

\frac{\partial}{\partial x} (7 x y^{6} + x^{4} y^{4})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (7 x y^{6}) + \frac{\partial}{\partial x} (x^{4} y^{4})

\frac{\partial}{\partial x} (7 x y^{6}) = 7 y^{6}

\frac{\partial}{\partial x} (x^{4} y^{4}) = 4 y^{4} x^{3}

= 7 y^{6} + 4 y^{4} x^{3}

\frac{\partial}{\partial x} (6 + 2 x)

x \to 2 lim (x^{3} - a x)

\int_{0}^{49} \frac{1}{49 - x} d x

x sin (\frac{5}{x})

\frac{d}{d x} (\frac{x}{1 - ln ( x - 9 )})

What is (\partial)/(\partial x)(7xy^6+x^4y^4) ?
The answer to (\partial)/(\partial x)(7xy^6+x^4y^4) is 7y^6+4y^4x^3