What is laplacetransform 5e^{-3t} ?

The answer to laplacetransform 5e^{-3t} is 5/(s+3)

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laplacetransform 5e^{-3t}

laplace transform

5 e^{- 3 t}

\frac{5}{s + 3}

Solution steps

L {5 e^{- 3 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {e^{- 3 t}}

L {e^{- 3 t}} : \frac{1}{s + 3}

= 5 \cdot \frac{1}{s + 3}

Refine

5 \frac{1}{s + 3} : \frac{5}{s + 3}

= \frac{5}{s + 3}

\frac{d}{d x} (A (e^{- x} - e^{- x} x))

y = 8 x arccos (x - 1), at x = 1

\int_{t}^{1} (\frac{1}{x ^{2}}) d x

(t^{2} + 5)^{2} - 7 (t^{2} + 5)

2 x \frac{d y}{d x} - 8 y = x^{- 8}

What is laplacetransform 5e^{-3t} ?
The answer to laplacetransform 5e^{-3t} is 5/(s+3)