What is the integral of sin(kx) ?

The integral of sin(kx) is -1/k cos(kx)+C

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integral of sin(kx)

\int sin (k x) d x

- \frac{1}{k} cos (k x) + C

Solution steps

\int sin (k x) d x

Apply u-substitution

: \int \frac{sin ( u )}{k} d u

= \int \frac{sin ( u )}{k} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{k} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{k} (- cos (u))

Substitute back

u = k x

= \frac{1}{k} (- cos (k x))

Simplify

= - \frac{1}{k} cos (k x)

Add a constant to the solution

= - \frac{1}{k} cos (k x) + C

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