What is the solution for -y^'+(2y)/x =(y^2)/x ?

The solution for -y^'+(2y)/x =(y^2)/x is y=-(2e^{2c_{1}}x^2)/(1-e^{2c_{1)}x^2}

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-y^'+(2y)/x =(y^2)/x

- y^{^{'}} + \frac{2 y}{x} = \frac{y ^{2}}{x}

y = - \frac{2 e ^{2 c_{1}} x ^{2}}{1 - e ^{2 c_{1}} x ^{2}}

Solution steps

- y^{'} (x) + \frac{2 y}{x} = \frac{y ^{2}}{x}

Solve separable ODE:

y = - \frac{2 e ^{2 c_{1}} x ^{2}}{1 - e ^{2 c_{1}} x ^{2}}

y = - \frac{2 e ^{2 c_{1}} x ^{2}}{1 - e ^{2 c_{1}} x ^{2}}

x \to \infty lim (ln (3 x) - ln (x + 7))

\frac{d y}{d t} = 2 y + 3 e^{2 t}

\frac{d}{d x} (2 x x^{2} + 1)

x \to 0 lim (\frac{( 9 ^{x} - 7 ^{x} )}{x})

\frac{\partial}{\partial x} (2 - 6 y)

What is the solution for -y^'+(2y)/x =(y^2)/x ?
The solution for -y^'+(2y)/x =(y^2)/x is y=-(2e^{2c_{1}}x^2)/(1-e^{2c_{1)}x^2}