What is the solution for y^'=1-(4y)/(100) ?

The solution for y^'=1-(4y)/(100) is y=-e^{(-t-c_{1})/(25)}+25

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y^'=1-(4y)/(100)

y^{^{'}} = 1 - \frac{4 y}{100}

y = - e^{\frac{- t - c _{1}}{25}} + 25

Solution steps

y^{'} (t) = 1 - \frac{4 y}{100}

Solve separable ODE:

y = - e^{\frac{- t - c _{1}}{25}} + 25

y = - e^{\frac{- t - c _{1}}{25}} + 25

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What is the solution for y^'=1-(4y)/(100) ?
The solution for y^'=1-(4y)/(100) is y=-e^{(-t-c_{1})/(25)}+25