What is the tangent of f(x)= 3/x ,\at x=2 ?

The tangent of f(x)= 3/x ,\at x=2 is y=-3/4 x+3

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tangent of f(x)= 3/x ,\at x=2

tangent of

f (x) = \frac{3}{x}, at x = 2

y = - \frac{3}{4} x + 3

Solution steps

Find the tangent point:

(2, \frac{3}{2})

Find the slope of

f (x) = \frac{3}{x} : \frac{df ( x )}{d x} = - \frac{3}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{4}

Find the line with slope m=

- \frac{3}{4}

and passing through

(2, \frac{3}{2}) : y = - \frac{3}{4} x + 3

y = - \frac{3}{4} x + 3

\frac{\partial}{\partial x} (ln (7 x^{2} + 4 y^{2} + 8))

y^{2} - 3 x = 4, x - y = 2

y = \frac{2}{x} - \frac{x}{2}

y = - sin (x) - \frac{1}{x}

x \to 3 + lim (5 x - [∣ x ∣])

What is the tangent of f(x)= 3/x ,\at x=2 ?
The tangent of f(x)= 3/x ,\at x=2 is y=-3/4 x+3