What is the derivative of y=ln(9x) ?

The derivative of y=ln(9x) is 1/x

What is the first derivative of y=ln(9x) ?

The first derivative of y=ln(9x) is 1/x

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derivative of

y = ln (9 x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (9 x))

Apply the chain rule:

\frac{1}{9 x} \frac{d}{d x} (9 x)

= \frac{1}{9 x} \frac{d}{d x} (9 x)

\frac{d}{d x} (9 x) = 9

= \frac{1}{9 x} \cdot 9

Simplify

\frac{1}{9 x} \cdot 9 : \frac{1}{x}

= \frac{1}{x}

x^{3} - 10 x^{2} + 24 x, - x^{3} + 10 x^{2} - 24 x

n = 1 \sum \infty (- 4)^{- n}

\frac{2 x ^{\frac{3}{2}} - x ^{2} + 4}{x}

\int \frac{t ^{3}}{3} d t

\int \frac{1}{x ^{2} + 6 x - 7} d x

What is the derivative of y=ln(9x) ?
The derivative of y=ln(9x) is 1/x
What is the first derivative of y=ln(9x) ?
The first derivative of y=ln(9x) is 1/x