What is the integral of 1/(sec(u)) ?

The integral of 1/(sec(u)) is sin(u)+C

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integral of 1/(sec(u))

\int \frac{1}{sec ( u )} d u

sin (u) + C

Solution steps

\int \frac{1}{sec ( u )} d u

Rewrite using trig identities

= \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= sin (u)

Add a constant to the solution

= sin (u) + C

3 y^{^{'}} + \frac{2 y}{x} = \frac{( y ^{4} )}{x ^{4}}

2 x^{3} + 3 x^{2} - 12 x + 7

y = x^{2}, y = 9, [- 3, 3]

x^{3} cos (x^{4})

x \to \infty lim (m x + b)