What is the limit as h approaches 0 of ((e^{2h}-1))/h ?

The limit as h approaches 0 of ((e^{2h}-1))/h is 2

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limit as h approaches 0 of ((e^{2h}-1))/h

h \to 0 lim (\frac{( e ^{2 h} - 1 )}{h})

2

Solution steps

h \to 0 lim (\frac{e ^{2 h} - 1}{h})

Apply L'Hopital's Rule

: h \to 0 lim (\frac{2 e ^{2 h}}{1})

= h \to 0 lim (\frac{2 e ^{2 h}}{1})

Plug in the value

h = 0

= \frac{2 e ^{2 \cdot 0}}{1}

Simplify

= 2

x, (x - 2)^{2}

\frac{d}{d y} (ln (\frac{x}{y}))

f (x) = x^{5}, (- 1, - 1)

x \to - \infty lim (e^{2 x})

x \to 2 + lim (\frac{1}{3 x - 6})

What is the limit as h approaches 0 of ((e^{2h}-1))/h ?
The limit as h approaches 0 of ((e^{2h}-1))/h is 2