What is (\partial ^2)/(\partial x\partial y)(y^5sin(3x)) ?

The answer to (\partial ^2)/(\partial x\partial y)(y^5sin(3x)) is 15y^4cos(3x)

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(\partial ^2)/(\partial x\partial y)(y^5sin(3x))

\frac{\partial ^{2}}{\partial x \partial y} (y^{5} sin (3 x))

15 y^{4} cos (3 x)

Solution steps

\frac{\partial ^{2}}{\partial x \partial y} (y^{5} sin (3 x))

\frac{\partial}{\partial x} (y^{5} sin (3 x)) = y^{5} cos (3 x) \cdot 3

= \frac{\partial}{\partial y} (y^{5} cos (3 x) \cdot 3)

\frac{\partial}{\partial y} (y^{5} cos (3 x) \cdot 3) = 15 y^{4} cos (3 x)

= 15 y^{4} cos (3 x)

n = 1 \sum \infty \frac{n 7 ^{n}}{n !}

\int 7 e^{5 x} d x

\int_{\frac{1}{2}}^{7} 12 x ln (2 x) d x

\frac{d y}{d x} = (x + y + 1)

\int - e^{4 x - 8} + 1 d x

What is (\partial ^2)/(\partial x\partial y)(y^5sin(3x)) ?
The answer to (\partial ^2)/(\partial x\partial y)(y^5sin(3x)) is 15y^4cos(3x)