What is the solution for y^{''}+10y=0,y(0)=2,y^'(0)=1 ?

The solution for y^{''}+10y=0,y(0)=2,y^'(0)=1 is y=2cos(sqrt(10)t)+1/(sqrt(10))sin(sqrt(10)t)

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y^{''}+10y=0,y(0)=2,y^'(0)=1

y^{^{''}} + 10 y = 0, y (0) = 2, y^{^{'}} (0) = 1

y = 2 cos (10 t) + \frac{1}{10} sin (10 t)

Solution steps

y^{''} (t) + 10 y = 0

Solve linear ODE:

y = 2 cos (10 t) + \frac{1}{10} sin (10 t)

y = 2 cos (10 t) + \frac{1}{10} sin (10 t)

\int sin (4 x + π) d x

\frac{1}{7 x}

(sin (\frac{3}{x}))^{^{'}}

\frac{d}{d x} (\frac{2 x ^{2}}{3})

What is the solution for y^{''}+10y=0,y(0)=2,y^'(0)=1 ?
The solution for y^{''}+10y=0,y(0)=2,y^'(0)=1 is y=2cos(sqrt(10)t)+1/(sqrt(10))sin(sqrt(10)t)