What is the derivative of f(3)=3x^2+15 ?

The derivative of f(3)=3x^2+15 is 6x

What is the first derivative of f(3)=3x^2+15 ?

The first derivative of f(3)=3x^2+15 is 6x

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derivative of

f (3) = 3 x^{2} + 15

6 x

Solution steps

\frac{d}{d x} (3 x^{2} + 15)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (15)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (15) = 0

= 6 x + 0

Simplify

= 6 x

n = 1 \sum \infty - \frac{( 1 ) ^{n}}{n}

\int sin (x) cos (d) x d x

\frac{d y}{d x} = 11 e^{x - y}

\frac{d}{d x} (tan (x) - x)

y^{^{''}} - 2 y^{^{'}} - 3 y = x

What is the derivative of f(3)=3x^2+15 ?
The derivative of f(3)=3x^2+15 is 6x
What is the first derivative of f(3)=3x^2+15 ?
The first derivative of f(3)=3x^2+15 is 6x