What is (\partial)/(\partial y)(-y^2) ?

The answer to (\partial)/(\partial y)(-y^2) is -2y

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(\partial)/(\partial y)(-y^2)

\frac{\partial}{\partial y} (- y^{2})

- 2 y

Solution steps

\frac{\partial}{\partial y} (- y^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 y^{2 - 1}

Simplify

= - 2 y

(3.6) (- 5.2)

\int_{1}^{12} - x^{2} - 11 x + 12 d x

\frac{d}{d x} \frac{( 2 x ^{2} + 10 ) ^{\frac{3}{2}}}{x - 1}

- 3 x

\int 9^{- x} d x

What is (\partial)/(\partial y)(-y^2) ?
The answer to (\partial)/(\partial y)(-y^2) is -2y