What is the derivative of 1/(2sqrt(x))+1/(4x^{3/4)} ?

The derivative of 1/(2sqrt(x))+1/(4x^{3/4)} is -1/(4x^{3/2)}-3/(16x^{7/4)}

What is the first derivative of 1/(2sqrt(x))+1/(4x^{3/4)} ?

The first derivative of 1/(2sqrt(x))+1/(4x^{3/4)} is -1/(4x^{3/2)}-3/(16x^{7/4)}

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derivative of

\frac{1}{2 x} + \frac{1}{4 x ^{\frac{3}{4}}}

- \frac{1}{4 x ^{\frac{3}{2}}} - \frac{3}{16 x ^{\frac{7}{4}}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x} + \frac{1}{4 x ^{\frac{3}{4}}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{2 x}) + \frac{d}{d x} (\frac{1}{4 x ^{\frac{3}{4}}})

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{4 x ^{\frac{3}{2}}}

\frac{d}{d x} (\frac{1}{4 x ^{\frac{3}{4}}}) = - \frac{3}{16 x ^{\frac{7}{4}}}

= - \frac{1}{4 x ^{\frac{3}{2}}} - \frac{3}{16 x ^{\frac{7}{4}}}

\frac{d}{d x} (\frac{x ^{2} - 2}{- x ^{2} + 1})

\frac{d}{d x} (arcsin (2 x - 1))

y^{^{''}} - 2 y^{^{'}} - 3 y = 3 e^{2 t}, y (0) = 1, y^{^{'}} (0) = 0

\frac{d}{d x} (30 e^{x})

\frac{d}{d x} (22 x)

What is the derivative of 1/(2sqrt(x))+1/(4x^{3/4)} ?
The derivative of 1/(2sqrt(x))+1/(4x^{3/4)} is -1/(4x^{3/2)}-3/(16x^{7/4)}
What is the first derivative of 1/(2sqrt(x))+1/(4x^{3/4)} ?
The first derivative of 1/(2sqrt(x))+1/(4x^{3/4)} is -1/(4x^{3/2)}-3/(16x^{7/4)}