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Popular >

xy^'+(1+xcot(x))y=0

Solution

x y^{^{'}} + (1 + x cot (x)) y = 0

Solution

y = \frac{c _{1}}{x sin ( x )}

Solution steps

x y^{'} (x) + (1 + x cot (x)) y = 0

Solve separable ODE:

y = \frac{c _{1}}{x sin ( x )}

y = \frac{c _{1}}{x sin ( x )}

Popular Examples

integral from 0 to 1 of (e^x)-(xe^{x^2})

\int_{0}^{1} (e^{x}) - (x e^{x^{2}}) d x

limit as x approaches infinity of 2g(x)x

x \to \infty lim (2 g (x) x)

derivative of 1/10 x-1/2

\frac{d}{d x} (\frac{1}{10} x - \frac{1}{2})

integral of (1+x^2)/(x-x^3)

\int \frac{1 + x ^{2}}{x - x ^{3}} d x

(dr)/(dθ)=-pisin(piθ),r(0)=3

\frac{d r}{d θ} = - π sin (π θ), r (0) = 3

Frequently Asked Questions (FAQ)

What is the solution for xy^'+(1+xcot(x))y=0 ?
The solution for xy^'+(1+xcot(x))y=0 is y=(c_{1})/(xsin(x))