What is the derivative of f(x)=2x^2-9x+10 ?

The derivative of f(x)=2x^2-9x+10 is 4x-9

What is the first derivative of f(x)=2x^2-9x+10 ?

The first derivative of f(x)=2x^2-9x+10 is 4x-9

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derivative of

f (x) = 2 x^{2} - 9 x + 10

4 x - 9

Solution steps

\frac{d}{d x} (2 x^{2} - 9 x + 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (9 x) + \frac{d}{d x} (10)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (10) = 0

= 4 x - 9 + 0

Simplify

= 4 x - 9

\int \frac{x - 3}{x} d x

x \to \infty lim (\frac{e ^{x^{2}}}{5 - x ^{3}})

\frac{d y}{d x} = y x^{2} + y x, y (0) = - 1

\int x^{2} 2^{x} d x

What is the derivative of f(x)=2x^2-9x+10 ?
The derivative of f(x)=2x^2-9x+10 is 4x-9
What is the first derivative of f(x)=2x^2-9x+10 ?
The first derivative of f(x)=2x^2-9x+10 is 4x-9