What is laplacetransform e^{t-1} ?

The answer to laplacetransform e^{t-1} is 1/(e(s-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform e^{t-1}

laplace transform

e^{t - 1}

\frac{1}{e ( s - 1 )}

Solution steps

L {e^{t - 1}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{- 1} L {e^{t}}

L {e^{t}} : \frac{1}{s - 1}

= e^{- 1} \frac{1}{s - 1}

Refine

e^{- 1} \frac{1}{s - 1} : \frac{1}{e ( s - 1 )}

= \frac{1}{e ( s - 1 )}

f (x) = \frac{- 2 ln ( x ) + 1}{x ^{3}}

ln (1 - 5 y)

\int_{0}^{2} \frac{1}{4 - t ^{2}} d t

x \to \infty lim (\frac{e ^{4 x}}{5 x})

What is laplacetransform e^{t-1} ?
The answer to laplacetransform e^{t-1} is 1/(e(s-1))