What is (\partial)/(\partial x)(ln(y)+4x) ?

The answer to (\partial)/(\partial x)(ln(y)+4x) is 4

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(\partial)/(\partial x)(ln(y)+4x)

\frac{\partial}{\partial x} (ln (y) + 4 x)

4

Solution steps

\frac{\partial}{\partial x} (ln (y) + 4 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (ln (y)) + \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (ln (y)) = 0

\frac{\partial}{\partial x} (4 x) = 4

= 0 + 4

Simplify

= 4

x \to - 3 lim (\frac{16 - x ^{\frac{4}{3}}}{4 - x ^{\frac{2}{3}}})

x \to 3 - lim (\frac{1}{3 - x})

\int k e^{3 x} d x

\frac{d}{d x} (x + 5 sin (x))

x \to 5 - lim (\frac{3}{x ^{2} - 25})

What is (\partial)/(\partial x)(ln(y)+4x) ?
The answer to (\partial)/(\partial x)(ln(y)+4x) is 4