What is the limit as h approaches 0 of sin(1/h) ?

The limit as h approaches 0 of sin(1/h) is diverges

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limit as h approaches 0 of sin(1/h)

h \to 0 lim (sin (\frac{1}{h}))

diverges

Solution steps

h \to 0 lim (sin (\frac{1}{h}))

Apply Limit Divergence Criterion:

diverges

= diverges

\int 2 sin^{3} (2 x) cos^{3} (2 x) d x

x \to + 10 lim (x)

\frac{d y}{d x} = x^{6} y^{- 7}, y (0) = 4

x \frac{d y}{d x} - (1 - x) y = x y^{2}

f (x) = e^{- x} - e^{- x} x

What is the limit as h approaches 0 of sin(1/h) ?
The limit as h approaches 0 of sin(1/h) is diverges