What is the tangent of y=x^2-3x-5,(2,-7) ?

The tangent of y=x^2-3x-5,(2,-7) is y=x-9

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tangent of y=x^2-3x-5,(2,-7)

tangent of

y = x^{2} - 3 x - 5, (2, - 7)

y = x - 9

Solution steps

Find the slope of

y = x^{2} - 3 x - 5 : \frac{d y}{d x} = 2 x - 3

Compute the slope of

y = x^{2} - 3 x - 5

(2, - 7) : m = 1

Find the line with slope m=

1

and passing through

(2, - 7) : y = x - 9

y = x - 9

\frac{d}{d x} (\frac{6000}{x})

\int sin^{6} (x) cos^{3} (x) d x

x \to 0 lim (x^{7 x})

\frac{3}{s ^{2} + 16}

n = 2 \sum \infty (\frac{1}{2})^{n}

What is the tangent of y=x^2-3x-5,(2,-7) ?
The tangent of y=x^2-3x-5,(2,-7) is y=x-9