What is the sum from n=0 to infinity of 1/((2n+1)^4) ?

The sum from n=0 to infinity of 1/((2n+1)^4) is converges

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sum from n=0 to infinity of 1/((2n+1)^4)

n = 0 \sum \infty \frac{1}{( 2 n + 1 ) ^{4}}

converges

Solution steps

n = 0 \sum \infty \frac{1}{( 2 n + 1 ) ^{4}}

Apply Series Comparison Test:

converges

= converges

x + 3 y = 34, x + 6 = y^{2}

\frac{d}{d x} (9 x^{2} e^{- x})

f (x) = \frac{5}{2} + \frac{3}{2} x

(arctan (7 x))^{2}

What is the sum from n=0 to infinity of 1/((2n+1)^4) ?
The sum from n=0 to infinity of 1/((2n+1)^4) is converges