What is the integral of (e^x)/((e^x-7)(e^{2x)+1)} ?

The integral of (e^x)/((e^x-7)(e^{2x)+1)} is 1/50 ln|e^x-7|+1/50 (-1/2 ln|e^{2x}+1|-7arctan(e^x))+C

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integral of (e^x)/((e^x-7)(e^{2x)+1)}

\int \frac{e ^{x}}{( e ^{x} - 7 ) ( e ^{2 x} + 1 )} d x

\frac{1}{50} ln ∣ e^{x} - 7 ∣ + \frac{1}{50} (- \frac{1}{2} ln e^{2 x} + 1 - 7 arctan (e^{x})) + C

Solution steps

\int \frac{e ^{x}}{( e ^{x} - 7 ) ( e ^{2 x} + 1 )} d x

Apply u-substitution

: \int \frac{1}{( u - 7 ) ( u ^{2} + 1 )} d u

= \int \frac{1}{( u - 7 ) ( u ^{2} + 1 )} d u

Take the partial fraction of

\frac{1}{( u - 7 ) ( u ^{2} + 1 )} : \frac{1}{50 ( u - 7 )} + \frac{- u - 7}{50 ( u ^{2} + 1 )}

= \int \frac{1}{50 ( u - 7 )} + \frac{- u - 7}{50 ( u ^{2} + 1 )} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{50 ( u - 7 )} d u + \int \frac{- u - 7}{50 ( u ^{2} + 1 )} d u

\int \frac{1}{50 ( u - 7 )} d u = \frac{1}{50} ln ∣ u - 7 ∣

\int \frac{- u - 7}{50 ( u ^{2} + 1 )} d u = \frac{1}{50} (- \frac{1}{2} ln u^{2} + 1 - 7 arctan (u))

= \frac{1}{50} ln ∣ u - 7 ∣ + \frac{1}{50} (- \frac{1}{2} ln u^{2} + 1 - 7 arctan (u))

Substitute back

u = e^{x}

= \frac{1}{50} ln ∣ e^{x} - 7 ∣ + \frac{1}{50} (- \frac{1}{2} ln (e^{x})^{2} + 1 - 7 arctan (e^{x}))

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= \frac{1}{50} ln ∣ e^{x} - 7 ∣ + \frac{1}{50} (- \frac{1}{2} ln e^{2 x} + 1 - 7 arctan (e^{x}))

Add a constant to the solution

= \frac{1}{50} ln ∣ e^{x} - 7 ∣ + \frac{1}{50} (- \frac{1}{2} ln e^{2 x} + 1 - 7 arctan (e^{x})) + C

f (x) = x cos (2 x)

\int x x + 11 d x

\frac{4}{2 + 2 x ^{2}}

\int e^{- (x^{2})} d x

x^{3}, 1

What is the integral of (e^x)/((e^x-7)(e^{2x)+1)} ?
The integral of (e^x)/((e^x-7)(e^{2x)+1)} is 1/50 ln|e^x-7|+1/50 (-1/2 ln|e^{2x}+1|-7arctan(e^x))+C